Given: △akl, ak=9 m∠k=90°, m∠a=60° find: the perimeter of △akl the area of △ akl

Perimeter of ΔAKL is, units.

Area of  ΔAKL is, square units

Step-by-step explanation:

Given: In ΔAKL , AK = 9 units , and .

In ΔAKL

Substitute the value AK = 9 units and to solve for KL ;

⇒

In right angle ΔAKL,

Using Pythagoras theorem;

                    ......[1]

Substitute AK = 9 units and in [1] to solve for AL;

Perimeter of triangle is the sum of all the sides.

Perimeter of triangle AKL = AK +KL +AL = units.

Formula for Area of right angle triangle is given by:

Area of triangle AKL=  

                                  = square units

the line of