Tickets to a play cost $4 in advance and $5 at the door. the theater club president wants to raise at least $400 from the ticket sales. if the club sells 40 tickets in advance, what is the least number of tickets the club needs to sell at the door to reach the president’s goal?

48 tickets

Step-by-step explanation:

I just had this question on a test and got it right! So this is how i did it:

if the advance price is $4, and you sell 40 tickets in advance, you do 40 times 4.

40 x 4 = 160

so you subtract the $160 from 400 and then that brings you $240 dollars left.

*these 240 dollars will be tickets bought at the door*

to determine the amount of tickets that need to be bought left, you need to do 240 divided by 5.

and that will give you a total of:

a least amount of 48 tickets

0.84 dang lotta people are looking for this lol or if you round up its 1 but the overall answer to that is 0.84

step-by-step explanation: