The graph represents jason's speed on a trip. what is the rate of change for the period of time between 10 and 20 minutes? a) 0 b) 1 c) 12 d) 13

From 10 minutes to 20 minutes there is no rate of change, it stays at a constant and steady rate

Your answer would be A) 0

1. isolate the variable, in this case, d. subtract 35.5 on both sides of the equation.2. 52 subtracted by 35.5 is 16.53. therefore your answer would be d= 16.5this is the basics of pre algebra, isolating variable through adding, subtracting, multiplying, and dividing, if you have any other questions to ask just comment!