What is the initial value of the function represented by this table? (5 points) x . y 0 . 5 1 . 9 2 . 13

5 is the initial value

Step-by-step explanation:

From the table we can see that the values of y are increasing by 4

Lets use two points and find out slope

we use points (0,5) (1,9)

slope m= 5

Now we use y=mx+b equation

m= slope and b= y intercept, plug in (0,5)  and find out b

y=4x+b

5= 4(0) +b

so b= 5

b=5 is the initial value of the function

5 is the initial value

Step-by-step explanation:

From the table we can see that the values of y are increasing by 4

Lets use two points and find out slope

formula of slope

slope=m=

putting points (0,5) (1,9) in equation of slope

m=

slope m= 4

we know y=mx+b

m= slope and b= y intercept, plug in (0,5)  and find out b

b=?

x=0

m=4

y=5

putting these values in y=mx+b

y=4x+b

5= 4(0) +b

so b= 5

b=5 is the initial value of the function

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2