How many distinguishable permutations of the letters in december are possible?

#1

avatar+17746

+10

This can be calculated by using a fraction:

Count the number of letters in the word (in this case, 9) and create the numerator by the factorial of that number.

Since there are 9 letters in the word COMMITTEE, the numerator is  9!

Count the number of times each different letter is used and create the numerator by multiplying together the factorials of those numbers.  OK, that description may be clear as mud, so here's an example:

For COMMITTEE, the C is used once:  1!, the O is used once: 1!, the M is used twice: 2!, the I is used once: 1!, the T is used twice: 2!, and the E is used twice: 2!.

Putting these together, the denominator is  1!·1!·2!·1!·2!·2!  

So the answer is:  9! / [ 1!·1!·2!·1!·2!·2!  ]  =  45360

(A couple things about the denominator:  you really don't need to write down all the 1!, because their values are 1, but if you do, the sum of the numbers used in the denominator is equal to the number of letters in the word.)

Another example:  MISSISSIPPI  =  11! / [ 1!·4!·4!·2! ]

step-by-step explanation:

answers available in this download

(pearson%2c%25202012)%2520bbs.pdf& usg=aovvaw1obmtxnfghfgxhx0urh_je

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29