Which equation represents the general form a circle with a center at (–2, –3) and a diameter of 8 units?

(x+2)^2+ (y+3)^2= 16

Step-by-step explanation:

Given

Centre(h,k)=(-2,-3)

h= -2

k= -3

Diameter=8 units

To find radius,

r=diameter/2

r=  8/2

r=4 units

The equation for a circle with center at (h,k) and radius r is:

(x-h)^2+ (y-k)^2= r^2

Putting in the values of h,k and r

(x-(-2))^2+ (y-(-3))^2= (4)^2

(x+2)^2+ (y+3)^2= 16

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

step-by-step explanation:

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when the line is dashed:

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this < inequality sign means:

about the problem:

srry i'm not done ! i'll