Martha can paint a room in 2 hours. jamie can paint the same room in 6 hours. how long, to the nearest tenth of an hour, will it take them to paint the room together?

It will take 1.5 hours to paint the room together

Step-by-step explanation:

Martha can paint a room in 2 hours. Jamie can paint the same room in 6 hours.

Work done by Martha in 1 hour =

Work done by Jamie in 1 hour =

Work one together in 1 hour =  

Now take common denominator to add both fractions

LCD = 6, Multiply the first fraction by 3

Now add the numerators

To find total hours of painting together, we take reciprocal of 2/3

Time taken to paint together =

It will take 1.5 hours to paint the room together

The nearest tenth of an hour, will it take them to paint the room together is 1.5 hours.

Given data:

Time taken by Martha to paint a room is, 2 hours.

Time taken by Jamie to pain the same room is, 6 hours.

Then work done by each of Martha and Jamie in 1 hour is given as,

Total work done in 1 hour is given as,

To find total hours of painting together, we take reciprocal of 2/3.

Then, time taken to paint together is, 3/2 = 1.5 hours.

Thus, we can conclude in the nearest tenth of an hour, will it take them to paint the room together is 1.5 hours.

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link

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2