Nfirst gear, or low gear, an automobile's engine runs about three times as fast as the drive shaft. in second gear, the engine does not have to run as fast; usually it runs about 1.6 times faster than the drive shaft. finally, in third, or high gear, the engine runs at the same speed as the drive shaft. engine speed = 1,850 r. p.m. transmission in second gear drive-shaft speed =

Consider the following cases

Case 1: In n first gear,  an automobile's engine runs about three times as fast as the drive shaft.

So, if Speed of Engine = 1,850 r.p.m

Then Speed of Drive Shaft   r.p.m

Case 2 : In second gear, the engine does not have to run as fast; usually it runs about 1.6 times faster than the drive shaft.

 So, if Speed of Engine = 1,850 r.p.m

Then Speed of Drive Shaft   r.p.m

Case 3:  Finally, in third, or high gear, the engine runs at the same speed as the drive shaft.

So, if Speed of Engine = 1,850 r.p.m

Then Speed of Drive Shaft is also equal to 1,850 r.p.m

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!

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