In how many ways can the letters of the word independence be arranged if all the words start with n and end with p.

1663200

Step-by-step explanation:

in the word independance there are 3n,4e,&2d,1l, and 1c

since letters are repeating we use the formula,

n!/p1!p2!p3!

total letters=12

so n=12

since 3n, 4e & 2d

p1=3, p2=4

p3=2

total arrangments= 12!/3!4!2!

=1663200

14.29%

step-by-step explanation:

12.4, 12.387, 12.26, 12.252, 6.241, 6.2, 6.015, 6.009, 1.411, 1.2, 1.056, 1.007, 0.31,   0.13, 0.5, 0.04

step-by-step explanation:

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