Y=-1/3x +1 find a perpendicular line from a point on (3,4)

y = 3x - 5

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = - x + 1 is in this form

with slope m = -

given a line with slope m then the slope of a line perpendicular to it is

= - = - = 3

y = 3x + c ← is the partial equation

to find c substitute (3, 4) into the partial equation

4 = 9 + c ⇒ c = 4 - 9 = - 5

y = 3x - 5 ← equation of perpendicular line

ιт ιѕ (9χ^5+10)(81χ^10-90χ^5+100)

step-by-step explanation:

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