Arectangle has a perimeter 86 cm and length 36 cm what is its width

w = 7cm

Step-by-step explanation:

Perimeter = 2 x length + 2 x width  = 2L  + 2w

 Width is 4 cm less than the length, so w = L-4

  36 = 2L + 2(L-4)

 36 = 2L + 2L - 8

 36 = 4L - 8

44 = 4L

 L = 11

w = 7

2(11) + 2(7) = 22 + 14 = 36

Length is 11, width is 7

7cm

Step-by-step explanation:

36x2= 72

86-72= 14

14/2= 7

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