An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute. which equation gives the height, h, of the airplane after m minutes? a) h = 2,000m + 28,000 b) h = 28,000m + 2,000 c) h = 2,000 − 28,000m d) h = 28,000 − 2,000m 30 points

Option D is correct.

An equation: h = 28000 -2000m

Step-by-step explanation:

Let h represents the height of the airplane and m represents the minutes.

As per the given statement: An airplane 28,000 feet above ground begins descending at a constant rate of 2,000 feet per minute.

At ground m = 0

h(0) = 28000 feet.

⇒ An airplane descending at a constant rate (r) = - 2000 feet per minute

then,

height(h) of the airplane after m minutes is given by:

h(m) = 28000 - rm ; where r is the rate descending at constant rate and m is the minutes.

Substitute the given values we get;

h(m)= 28000 -2000m

Therefore, an equation which gives the height, h of the airplane after m minutes is; h = 28000 -2000m

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step-by-step explanation:

i believe that the answer is

b. y-1=-2(x-4)

hope this !