Amiddle school keeps track of its population. in 2011, the school population was 1500 students. in 2012, the student population had increased by 10%. in 2013, the student population had decreased by 10%. andy believes that the 2013 student population is the same as the 2011 student population since the population both increased and decreased by the same percentage. identify and explain the flaw in andy's reasoning. determine the percent change in the number of students from 2011 to 2013.

-1%

Step-by-step explanation:

The population will not be the same unless the starting value is the same. Percent is a portion of the total 100%. If the total in 2011 and 2012 was different, then the change in population will be different.

To find the percent change,

To calculate the percent increase or decrease, we:

The population originally in 2011 was 1500. In 12013, the population is 1485.

1485-1500=-15

-15/1500=-0.01

100(-0.01)=-1%

0.75(100)=75%

The towns population increase by 75%

y = 2x

step-by-step explanation:

if you divide each number in the sequence, you'll see that they all have a multiple factor of 2. each number in the series, and any other numbers which may continue, will be multiplied by 2. therefore, y is the next number in the sequence, and x is the current one, so, our formula will be y = 2x.