11. an object is thrown in the air with an initial velocity of 5 m/s from a height of 9 m. the equation h(t)-4.95t9 models the height of the object in meters after t seconds. about how many seconds does it take for the object to hit the ground? round your answer to the nearest tenth of a second.

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

x is greater than 5

step-by-step explanation:

2x+7 is greater than 17

    -7                           -7

2x is greater than 10

divide by 2 each side

x is greater than 5