Standard fif.2 dok: 18. an outfielder throws a ball vertically upward with a velocity of 30 meters per second. its distance from the ground after t seconds is approximately equal to 30t -5t2 meters. how many seconds will it take the ball to reach its maximum distance from the ground?

t = 3

Step-by-step explanation:

y = - 5t^2 + 30t                  Take out - 5 as a common factory = -5(t^2 - 6t)                     Complete the squarey = -5(t^2 - 6t + (6/2)^2)      Add (6/2)^2 outside the brackets. Why add?y = -5(t^2 - 6t + 9) + 9         Express the bracketed part as a perfect squarey = -5(t - 3)^2 + 9    The highest point reached will be nineThat occurs when -5(t -3)^2 = 0That happens when t = 3

Jim has run 5/6 of a mile so far. i hope that answers your question! good luck : )