What is the general equation of a circle centered at the origin?

It is x2+y2−169=0.

Explanation:

The circle you are looking fore is composed by all the points with a distance from the origin of 13/ The distance of a point from the center is

d=√x2+y2 and this distance has to be 13, so

13=√x2+y2 and to obtain the equation we can do the square

132=x2+y2 and the final equation is

x2+y2−169=0.

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation: