Hi can someone plz me i have no clue how to do this sos. ! ❤️❤️❤️

Problem 1)

This question is incomplete. It asks us to find something, but doesn't say what to find. It's literally blank after the word "find" which suggests your teacher made a typo. Please get back to me on this. Thanks.

Problem 2)

Angles GAR and GAT are supplementary because they are a linear pair. They form a straight angle. So we add up the expressions of x for each of these angles, solve for x, and use this to find angle GAR.

(angle GAR) + (angle GAT) = 180

(5x) + (3x+4) = 180

8x+4 = 180

8x+4-4 = 180-4

8x = 176

8x/8 = 176/8

x = 22

Note: now that I reached this point I realize that this might be the answer to problem 1; however, I'm not 100% sure because of the incomplete problem.

Use this x value to find angle GAR

angle GAR = 5*x

angle GAR = 5*22

angle GAR = 110

Unfortunately this answer isn't listed. I'm thinking your teacher made another typo.

Problem 3)

angle GAR and angle ABQ are corresponding angles.

Thankfully this answer is listed. Corresponding angles are angles that are on the same side of the transversal line and they are either both above or below the parallel lines they are next to. In this case, they are both above the parallel line counerparts.

Problem 4)

Corresponding angles are congruent as long as we have a set of parallel lines. So that means angle ABQ is equal to angle GAR. So angle ABQ is also 110 degrees

Problem 5)

angle BAT = angle GAR,  because they are vertical angles

angle BAT = 110

angle BAT = (angle BAD) + (angle DAT)

(angle BAD) + (angle DAT) = angle BAT

(100) + (angle DAT) = 110

angle DAT = 110-100

angle DAT = 10

angle ADB = angle DAT,  because they are alternate interior angles

angle ADB = 10

Final 10 degrees

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3