$1800 is invested at 4% compounded annually. find the future value of the investment in 5 years. find the interest that the investment will earn after the term.

the interest that the investment will earn after the term is $38.97

Step-by-step explanation:

1,800 x .04 x 1/2 = 36 (interest earned after 1 year)

1,800 + 36  = 1,836

1,836 x .04 x 1/2 = 36.72 (interest earned after 2 years)

1,836 + 36.72 = 1,872.72

1,872.72 x .04 x 1/2 = 37.4544 -> 37.45 (interest earned after 3 years)

1,872.72 + 37.45 = 1,910.17

1,910.17 x .04 x 1/2 = 38.2034 -> 38.20 (interest earned after 4 years)

1,910.17 + 38.20 = 1,948.37

1,948.37 x .04 x 1/2 = 38.9674 -> 38.97 (interest earned after 5 years)

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation: