If an object is dropped from a height of 55 feet, the function d = -16^2 + 55 gives the height of the object after t seconds. graph this function. approximately how long does it take the object to reach the ground (d=0)

t is approximately 1.854049622 seconds

Step-by-step explanation:

d = -16 t^2 + 55

Let d = 0

0 = -16 t^2 + 55

Subtract 55 from each side

-55 = -16 t^2

Divide by -16 on each side

-55/-16 =  -16 /-16t^2

55/16 = t^2

Take the square root of each side

sqrt(55/16) = sqrt(t^2)

We only take the positive square root because time must be positive

sqrt(55/16) = t

t is approximately 1.854049622 seconds

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