Which is an equation of the line that is perpendicular to 3x+y=-5 and passes through the point (3, -7)?

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

Step-by-step explanation:

First put 3x+y=5 in slope-intercept form (y=mx+b)

y=-3x+5

Give that the slope is -3 the perpendicular slope would be 1/3

now using the points (3.-7)

y+7=1/3(x-3) in point slope

y=1/3x-8 in slope intercept form

Put it in Slope - Intercept Form:

3x + y = -5

-3x         -3x

y = -3x - 5

Now plug in the ordered pair that is given:

(3, -7)

y = -3x - 5

-7 = -3(3) - 5

-7 = -9 - 5

-7 = -14

NO, it's false

Hi, really really sorry if I am incorrect...

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*

step-by-step explanation:

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