Which subtraction expression has the difference 1 + 4i? (–2 + 6i) – (1 – 2i) (–2 + 6i) – (–1 – 2i) (3 + 5i) – (2 – i) (3 + 5i) – (2 + i)

(3 + 5i) – (2 + i)

Step-by-step explanation:

(–2 + 6i) – (1 – 2i)

The real parts  -2-1 = -3

The imaginary parts 6i--2i = 6i+2i = 8i

(–2 + 6i) – (–1 – 2i)

The real parts -2 +1 = -1

The imaginary parts 6i --2i = 6i+2i =8i

(3 + 5i) – (2 – i)

The real parts 3-2 =1

The imaginary parts = 5i --i = 5i+i = 6i

(3 + 5i) – (2 + i)

The real parts 3-2 =1

The imaginary parts 5i -i = 4i

option 1 is correct.

step-by-step explanation:

y varies inversely with x and constant of variation is 4

the equation will be:

y = k/x

where k =4 so,

y = 4/x

if we put values of x of option 1 in the above equation and find values of y

y = 4/-2 => y =-2

y = 4/-1 => y = -4

y = 4/1 => y = 4

y = 4/2 => y =2

so, all the values of x and y are correct.

if we put values of x given in other options and find value of y we cannot find whole table satisfying the equation.

hence option 1 is correct.