Marie placed two orders at the same restaurant last month. in one order, she received 5 trays of lasagna and 3 trays of garlic bread for $163. in the other order, she received 4 trays of lasagna and 4 trays of garlic bread for $150.80. what is the price for one tray of lasagna, l, and one tray of garlic bread, g? l = $24.95 g = $12.75 l = $12.75 g = $24.95 l = $24.75 g = $12.95 l = $12.95 g = $24.75

L=$24.95 , G=$12.75

Step-by-step explanation:

This problem is a classic system of equations problem.  There are several methods of solving these problems, because of the circumstances and values given I think it's best to use the elimination method.  The elimination method attempts to cancel out a variable by subtracting one equation from another.  

The first statement Marie received an order of 5 trays of lasagna and 3 trays of garlic bread for a total of $163.  I'm going to use "L" for lasagna and "G" for garlic bread.  Therefore, the equation for the scenario above is:

In the second statement Marie received an order of 4 trays of lasagna and 4 trays of garlic bread and so:

Now we cannot use the elimination method directly because equation 1 and equation 2 do not have any coefficients in common.  However, we can eliminate "G" by first multiplying the top equation by 4 and the bottom equation by 3.  We are doing this because those are the coefficients of the other equation, and thus will return a common value as such:

Equation 1:

Equation 2:

Now we can subtract equation 2 from equation 1 and eliminate the "G" variable as such:

By solving for L we obtain:

Therefore, one tray of lasagna is $24.95.  Now that we know the value of "L" we can use any of our original equations to figure out what "G" is.  I'll use the first equation and so:

And so the price of a tray of garlic bread is $12.75.  So the answer is the price of lasagna = $24.95  and garlic bread = $12.75

~~~Brainliest Appriciated~~~