The graph below shows the solution to a system of inequalities: solid line joining ordered pairs 0, 4 and 9, negative 8. shade the portion of the graph below the line in the first and fourth quadrant which of the following inequalities is modeled by the graph? 4x + 3y ≤ 12; x ≥ 0 4x + 3y ≥ 12; x ≥ 0 4x − 3y ≤ 12; x ≥ 0 −4x − 3y ≤ 12; x ≥ 0

4x + 3y ≤ 12; x ≥ 0

The points (0, 4) and (9, -8) are on the line 4x+3y = 12. Shading below the solid line indicates the relation is "≤". These conditions match the first selection only.

The condition x ≥ 0 matches shading in the 1st and 4th quadrants only.

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1