Which equation could generate the curve in the graph below? y = 9x2 + 6x + 4 y = 6x2 – 12x – 6 y = 3x2 + 7x + 5 y = 2x2 + 8x + 8

y = 2x^2 + 8x + 8

Step-by-step explanation:

The graph touches the x axis at only one point.

so there is only one real solution.

If there is only one real solution then determinant =0

Now we find out the equation that has determinant 0

Determinant is

Let find b^2 - 4ac for each equation

(a)

a= 9 , b = 6 and c=4

determinant not equal to 0

(b)

a= 6 , b = -12 and c=-6

determinant not equal to 0

(c)

a= 3 , b = 7 and c=5

determinant not equal to 0

(d)

a= 2 , b = 8 and c=8

determinant equal to 0. So there is only one real solution.

36

step-by-step explanation:

d. 8

step-by-step explanation:

the given radical expression is:

we can rewrite this as:

we express as square numbers to get;

the exponents will now cancel out to give.

the correct answer is d