1) what is the solution of the given system? 5x-y=-7 3x-y=-2 a: (-2.5,-5.5) b: (-2.5,11) c: (5,2.5) d: (2.5,5.5) 2) what is the solution of the given system? 5x+7y=32 8x+6y=46 a: (8, 5) b: (1, 5) c: (7, 0) d: (5, 1)

1  x=-2.5  y = -5.5

2.  x=5  y=1

Step-by-step explanation:

1) What is the solution of the given system?

5x-y=-7

3x-y=-2

Multiply the second equation by -1

-1*(3x-y)=-1(-2)

-3x +y = 2

Now add the first equation to the modified second equation

5x-y=-7

-3x +y = 2

2x = -5

Divide each side by 2

2x/2 = -5/2

x = -2.5

Now we need to find y

-3x+y =2

-3(-2.5) +y =2

7.5 +y =2

Subtract 7.5 from each side

7.5 -7.5 +y =2-7.5

y = -5.5

2) what is the solution of the given system?

5x+7y=32

8x+6y=46

Divide the second equation by 2

8x/2+6y/2=46/2

4x+3y =23

Multiply the first equation by 4

4 (5x+7y)=32*4

20x+28y = 128

Now multiply the modified 2nd equation by -5

-5(4x+3y )=-5(23 )

-20x -15y = -115

Lets add the new equations together to eliminate x

20x+28y = 128

-20x -15y = -115

      13y = 13

Divide each side by 13

13y/13 =13/13

y=1

Now substitute back in to find x

5x+7y=32

5x +7(1) =32

5x +7 =32

Subtract 7 from each side

5x+7-7 =32-7

5x =25

Divide by 5

5x/5 =25/5

x=5