What is the greatest possible integer value of x for whichsquare root of x-5 is an imaginary number?

4

Step-by-step explanation:

√x imaginary if and only if x < 0

√(x-5) imaginary ifi x-5 < 0

x<5

4 is the largest integer < 5.

d

step-by-step explanation:

i used the pitagoras theoreme

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.