If the domain of f (x ) = 4 +x2 is {-1, 0, 1, 2}, what is the range?

y = {5, 4, 8}

Step-by-step explanation:

f(x) = 4 + x²

f(-1) = 4 + (-1)²

      = 4 + 1

      = 5

f(0) = 4 + (0)²

      = 4 + 0

      = 4

f(1) = 4 + (1)²

      = 4 + 1

      = 5

f(2) = 4 + (2)²

      = 4 + 4

      = 8

Put the values from domain to the equation of the function.

f(x) = 4 + x²

f(-1) = 4 + (-1)² = 4 + 1 = 5

f(0) = 4 + 0² = 4 + 0 = 4

f(1) = 4 + 1² = 4 + 1 = 5

f(2) = 4 + 2² = 4 + 4 = 8

this shows a reflection over the x-axis and is translated one unit down and 6 units to the right (x + 6, y - 1)

hope this !

~just a girl in love with shawn mendes

3100

step-by-step explanation: