Atourist starts to walk up a mountain path that is 31 miles long at the rate of 4 miles per hour. after walking for a while, he gets tired and decides to get a taxi. the taxi gets him to the top travelling at a constant speed of 50 mph. if the tourist reaches the destination 2 hours after he started, what distance does he have to pay the cab driver for?

Distance that must be paid to the taxi = 25 miles

Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration

• At constant velocity motion:

the speed of vo = v = constant

acceleration = a = 0

An equation of constant velocity motion

x = distance = m

v = speed = m / s

t = time = seconds

so

A mountain path is 31 miles long

The distance traveled by tourists = x1

The distance traveled taxi = x2, such that

x1 + x2 = 31

x1 = 31-x2

total travel time (t) = 2 hours

tourist speed = v1 = 4 mph

taxi speed = v2 = 50 mph

time taken by tourists = t1

the time taken by taxi = t2

total time = t1 + t2

The distance of the elevator

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resultant velocity

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the average velocity

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-362

step-by-step explanation:

(12)(4)+2(12)-34(12)+2(12)-3

  \/         \/         \/         \/

  48 +   24 -   408 + 24 - 3

      \   /               \   /

          72     -     432 - 3 = -363