Suppose a normal distribution has a mean of 38 and a standard deviation of 2. what is the probability that a data value is between 36 and 43? round your answer to the nearest 10th of a percent.

83.5 %

Step-by-step explanation:

The mean is 38 and the standard deviation is 2

38 -2 is 36

36 is one standard deviation below the mean.

43 - 38 is 5

5/2 is 2 1/2 times the standard deviation above the mean

-1< z< 2.5

P ( Z<2.5 )−P (Z<−1 )

P ( Z<−1)=1−P ( Z<1 )

P ( Z<2.5 )-1+P ( Z<1 )

Using the standard normal table

0.9938 - 1 +0.8413

0.8351

83.51%

Rounding to the nearest tenth

83.5%

this doesn't make sense lol

answer: h

step-by-step explanation: