Two runners start 30kilometer apart and run toward each other. they meet after 3hours. one runner runs 2 kilometers per hour faster than the other runner. what rate do they run

Let the slower runners speed be X kilometers per hour.

Then the faster runners speed would be X+2 kilometers per hour.

The formula for distance is Speed times time.

The distance is given as 30 kilometers and time is given as 3 hours.

Since there are two runners you need to add the both of them together.

The equation becomes 30 = 3x + 3(x+2)

Now solve for x:

30 = 3x + 3(x+2)

Simplify:

30 = 3x + 3x +6

30 = 6x + 6

Subtract 6 from each side:

24 = 6x

Divide both sides by 6:

x = 24/6

x = 4

The slower runner ran at 4 kilometers per hour.

The faster runner ran at 4+2 = 6 kilometers per hour.

1     sepan

2     encuentren

3     tenga

4     hable

5   parezca

6   llegue

answer: bearing in mind that a rectangle has a perimeter of length + length + width + width.

step-by-step explanation:

p = perimeter

l = length

x=width

p = 2l + 2x

p = 2(l+x)     < ==== perimeter of the base of the box.