What are the real and complex solutions of 0=x^4+3x^2-4

(2i,0) (-2i,0)

(1,0) (-1,0).

Step-by-step explanation:

The graph below shows that there are only 2 real solutions at x = 1 and x = - 1

Expressed as points, these two are (1,0) and (-1,0). However that is not the complete answer. There are 2 complex points.

y = x^4 + 3x^2 - 4

y = (x^2 - 1)(x^2 + 4)

These two binomials can be equated to 0

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