Find an equation for the line that passes through the points , −3−3 and , 5−1 .

y +3 = (1/4)(x +3)

The two-point form of the equation for a line is good for this.

... y -y1 = (y2-y1)/(x2-x1)(x -x1)

Substituting your values, we have ...

... y -(-3) = (-1-(-3))/(5-(-3))(x -(-3))

... y +3 = 2/8(x +3)

Since you ask for "an equation," we can leave it in this form.

... y +3 = (1/4)(x +3)

Or we can rearrange it to slope-intercept form:

... y = (1/4)x -(2 1/4)

or put it in standard form:

... x -4y = 9

im trinna find out'

step-by-step explanation: