An animal shelter has a ratio of dogs and two cats that are a 3.2 and there are 30 cats at the shelter how many dogs are there

We have 45 dogs when we have 30 cats

Step-by-step explanation:

If the ratio of dogs to cats is 3:2

We want to get to 30 cats so we need to multiply by 15  (2*15 =30)

What we do on one side we do on the other

3*15 : 2 * 15

45 :30

We have 45 dogs when we have 30 cats

hi! i think the answer is 1/2 : )

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)