Astudy found that out of 300 people 60% of them prefer to eat hamburgers rather than hot dogs. find the 95% confidence interval for the true proportion of people who prefer to eat hamburgers rather than hot dogs in the entire population.

(0.5446, 0.6554)

Step-by-step explanation:

As the sample is sufficiently large, the formula is used to estimate the proportion shown in the attached image.

Where:

P: sample proportion = 0.6

n: Sample size = 300

: Confidence level = 0.95

α: Significance = 0.05

*

* Obtained from the normal standard table.

When introducing these values in the formula shown in the image we obtain:

Finally, the confidence interval is:

(0.5446, 0.6554)

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol