Plz do asap need like now me plz what is the equation of this graphed line? y = mx + b m is the slope b is the y intercept (where does the line cross the y - ordered pair) x and y can be a point on the line m = y2 - y1/x2 - x1 a graph with a line running through coordinates (-4, -6) and coordinates (2, 6) enter your answer in slope-intercept form in the box.

y = 2x+2

Step-by-step explanation:

When we have 2 points, we can find the slope from

m = (y2-y1)/(x2-x1)

   = (6--6)/(2--4)

   = (6+6)/(2+4)

   = 12/6

  = 2

The slope is 2

We can use the point slope form of the equation for a line

y-y1 = m(x-x1)

y-6 = 2(x-2)

We need to get this in slope intercept form

Distribute the 2

y-6 = 2x-4

Add 6 to each side

y-6+6 = 2x-4+6

y = 2x+2

y = 2x + 2

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + b ( m is the slope and b the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (- 4, - 6) and (x₂, y₂ ) = (2, 6)

m = = = 2, hence

y = 2x + b is the partial equation

to find b substitute either of the 2 points into the partial equation

using (2, 6), then

6 = 4 + b ⇒ b = 6 - 4 = 2

y = 2x + 2 ← equation in slope-intercept form

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.