You roll a fair six-sided die twice. what is the probabilty of rolling an even number then rolling an odd number?

Probability of rolling an even number then rolling an odd number = 1/4

Step-by-step explanation:

When we roll a fair six-sided die twice,

The pair of combinations are

(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(5,1),(6,2),(6,3),(6,4),(6,5),(6,6)

There are 36 possibilities

The odd numbers are 1,3 and 5

even numbers are 2,4 and 6

Possibilities of rolling an even number then rolling an odd number

(2,1),(2,3),(25)

(4,1),(4,3),(4,5)

(6,1),(6,3),(6,5)

There are 9 possibilities

Probability of rolling an even number then rolling an odd number = 9/36 = 1/4

e

step-by-step explanation:

an equation by definition has to have two or more variables (x and 2 in this case)

where is the diagram? shown below where? ?

step-by-step explanation: