In isosceles right triangle abc, point is on hypotenuse \overline{bc} such that \overline{ad} is an altitude of \triangle abc and dc = 5. what is the area of triangle abc?

Area of triangle is 25.

Step-by-step explanation:

We have been given an isosceles right triangle

Isosceles triangle is the triangle having two sides equal.

Figure is shown in attachment

By Pythagoras theorem

AD is altitude which divides the triangle into two parts

DC=5 implies BC =10 since D equally divides BC

Let AC=a implies AB=a being Isosceles

On substituting the values in the Pythagoras theorem:

WE can find area of right triangle by considering height AB and AD

Area of triangle ABC is:

    (1)

And other method of area of triangle is:

      (2)

Equating (1) and (2) we get:

Using area of triangle is:

Now, the area of triangle ABC=

11

step-by-step explanation:

32.50-7.50=25

225/25=11

6.5

step-by-step explanation:

you said it was in the question

~courtney