If abe is similar to acd what is the value of ab

AB corresponds to AC. Both are the left diagonal lines of triangle ABE and triangle ACD. Both AB and AC are also the first two letters of ABE and ACD respectively

BE and CD correspond as well. They are the horizontal sides of the two triangles. BE and CD are the last two letters of ABE and ACD.

Set up the proportion below. Then solve for x

AB/AC = BE/CD

AB/(AB+BC) = BE/CD

x/(x+3) = 2/5

5x = 2(x+3)

5x = 2x+6

5x-2x = 6

3x = 6

x = 2

AB = 2

note how AB = x = 2, so AC = AB+BC = x+3 = 2+3 = 5. This forms the ratio AB/AC = 2/5 which is identical to the ratio BE/CD = 2/5

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.