Given: δacm, m∠c = 90ºcp ⊥ am , ac = 15 ap = 9, pm = 16 find: cp, cm

CM=20 and CP=12

Step-by-step explanation:

The given triangle ΔACM has the measurements as follows:

m∠C=90°, CP⊥AM, AC=15, AP=9, PM=16.

To Find: CP and CM

We can use Pythagoras theorem to calculate the sides CP and CM.

Pythagoras theorem gives a relation between hypotenuse, base and height/perpendicular of a right angled triangle which is as follows:

where h is hypotenuse of triangle, b is base and p is perpendicular of triangle.

The figure shows that in ΔACM is a right angled triangle at C where,

AM --> hypotenuse

CM --> base

AC --> height

So substituting values into formula:

, which is required answer.

Similarly, we can see that triangle ΔCPM is also a right angled triangle at P and thus Pythagoras theorem can again be applied to calculate CP. Since CM is the side opposite to right angle P, it is the hypotenuse.

So we have,

, which is required answer.

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

19

step-by-step explanation: