What is the axis of symmetry for f(x) = 2x2 − 4x + 5? (1 point) x = −2 x = −1 x = 1 x = 2

y = 2x^2 − 4x + 5

y = 2(x^2 − 2x) + 5

y = 2(x^2 − 2x + 1 - 1) + 5

y = 2(x^2 − 2x + 1) + 5 - 2

y = 2(x - 1)^2 + 3

x = 1 is the axis of symmetry.

Do you agree?

x = 1

Step-by-step explanation:

To find the axis of symmetry use the formula: x = -b/2a. In the quadratic equation of 2x^2 - 4x + 5:

Substitute a and b into the formula.

x = -(-4)/2(2)

This simplifies to 4/4, which is then simplified to 1.

Therefore the axis of symmetry is x = 1.

answer: a. 74

step-by-step explanation:

it shows divided evenly, so add the 37+37 = 74