Afootball is kicked at 40 yards away from a goal post that is 10 feet high. its path is modeled by y = -0.03x 2 + 1.6x, where x is the horizontal distance in yards traveled by the football and y is the corresponding height above the ground in feet. does the football go over the goal post? how far above or below the goal post is the football? use two or more complete sentences to explain your answers. (hint: the unit conversion is built into the given function.)

The football is going to go over the goal post.  It will clear the goal post by (16-10)  6 ft

Step-by-step explanation:

y = -0.03x^2 + 1.6x

Let x = 40

We need to determine if y> 10

y = -0.03(40)^2  + 1.6(40)

y = -48+64

y =16

Since 16>10

The football is going to go over the goal post.  It will clear the goal post by (16-10)  6 ft

d. 145*2 is 290 than the total angle is 360 then minus 290 then divide by two

answer: cos [   arcsin (3/5) - arccos (1/2) ] =

step-by-step explanation: × = 3/5 = 0.6--> x = 36.87 and x = 180 - 36.87 = 143.13 deg

cos y = 1/2 --> y = +- 60 deg a. cos (x - y) = cos (143.13 - 60) = cos 83,13  

=

0.12

b. cos (36.87 - 60) = cos (-23.23) = 0.92