Iwill award ! find the value of x in each case b, c ∈ ad

So first let's find ∠BCE: (Assume that the line ABCD is a straight line)

The angle on a line is 180°.

So ∠BCE = 180° - 64° - 90° = 26°

Now, let's find ∠EBC:

∠EBC = 180° - 3x.

The sum of the angles in a triangle is also 180°. So if you add up the angles in the triangle, you should get 180°.

∠BCE + ∠EBC + ∠BEC = 180°

26° + (180° - 3x) + x = 180°

Now, combine like terms:

206° - 2x = 180°

Subtract both sides by 206°.

-2x = -26

Divide both sides by -2 and you'll get:

x = 13°.

not solvable

step-by-step explanation:

we need more information, or at least an

where is the figure