Identify the quadrant where each point is located. (-5,2) (5,-5) (2,-5) (-4,-5)

(-5,2) is located in the II quadrant because the x is negative and the y is positive.

(5,-5) is located in the IV quadrant because the x is positive and the y is negative.

(2,-5) is also located in the IV quadrant because the x is positive and the y is negative.

(-4,-5) is located in the III quadrant because both x and y are negative.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

∡ eia and ∡ kij are congruent

step-by-step explanation: