Tickets sold in advance cost $3. tickets sold at the door cost $5. if 100 tickets were sold for a total of $460, how many tickets were sold at the door?

80 tickets

Step-by-step explanation:

Let x be the number of tickets that were sold at the door and y be the number of tickets that were tickets sold in advance. So we can write an equation for the total amount of money as:

5x + 3y = 460 --- (1)

and equation for the number of tickets sold as:

x + y = 100 --- (2)

From equation (2),  we get y = 100 - x.

Substituting this value of x in equation (1) to get:

5x + 3(100 - x) = 460

5x + 300 - 3x = 460

5x - 3x = 460 -300

2x = 160

x = 80

Therefore, 80 tickets were sold at the door.

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb