Write an equation in slope-intercept form for the line with slope 3 that contains the point (5,-1).

y = 3x-16

Step-by-step explanation:

We know the slope and a point , so we can use the point slope form of the equation for a line

y-y1 = m(x-x1) where the slope is m and the point is (x1,y1)

y--1 = 3(x-5)

y+1 = 3(x-5)

We need to rearrange the equation into slope intercept form  y=mx+b

First distribute the 3

y+1 =3x-15

Then subtract 1 from each side

y+1-1 =3x-15-1

y = 3x-16

This is in slope intercept form

The point-slope form:

m - slope

(x₁, y₁) - point

We have the slope m = 3 and the point (5, -1). Substitute:

Convert to the slope-intercept form:

         use distributive property a(b + c) = ab + ac

          subtract 1 from both sides

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation: