Given: △ace, bd∥ae prove: ba/cb=de/cd drag

Step-by-step explanation:

Angle 4 = angle 1 and angle 3 =angle 2        Corresponding angles for two        parallel lines BD and AE

Triangle AED ||| BDE                                       Angle angle congruent

...                                                                       By compendo and dividendo

Thus proved

Since two lines are parallel we have corresponding angles equal and also

sides will be proportional in similar triangles

Using that and adjusting compendo and dividendo we get the desired result

The missing phrase or expression that completes the proof are:

From the diagram given, <4 and <1 are corresponding angles, so also <3 and <2.

Corresponding angles are always equal/congruent.

Since both have two pairs of congruent angles, therefore, based on the Angle-Angle Similarity postulate:

Also, the segment addition postulate states that if a segment is consist of two small segments, its length will be the sum of the two small segments.

Therefore, the reason that justifies why CA = CB + BA, and CE = CD + DE is:

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step-by-step explanation:

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3, 12, 48, 384, 1536, 6144, 24576, 98304

step-by-step explanation:

just keep timing it by 4.