Write an equation in slope intercept form of the line with q slope of -3/4 and y intercept of -5

y = (-3/4)x - 5

Step-by-step explanation:

The general form of the slope-intercept equatin of a straight line is

y = mx + b, where m is the slope  and b is the y-intercept.

Substituting -3/4 for m and -5 for b, we get:

y = (-3/4)x - 5

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

i only know the sequence of arithmetic it adds the first is 5+4 then it goes up as it adds to then it is 9+5 then 14+6 then to 20+7 and so on. 5,9,14,20,27,35.

step-by-step explanation: