In a city school, 60% of students have blue eyes, 55% have dark hair, and 35% have blue eyes and dark hair. what is the probability (rounded to the nearest whole percent) that a randomly selected student has dark hair, given that the student has blue eyes?

60% have blue eyes.

35% have blue eyes and dark hair.

Divide the percent that has both blue eyes and dark hair by the percent who have blue eyes:

35 / 60 = reduces to 7/12 = 58.3% have dark hair given they have blue eyes.

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)

answer: about 22.67

step-by-step explanation: