Can someone me solve this system of equations

x=15 and y=2

Step-by-step explanation:

The given system of equations is

8y - x = 1                    (i)

and

10 y = x + 5                 (ii)

Now from equation (ii)

10 y = x + 5

subtracting -5 from both sides

10 y - 5 = x + 5 - 5

10 y -5 = x  

or

x = 10y -5 (iii)

Put this in equation (i)

it becomes

8y - (10y -5) = 1

8y-10y+5=1

-2y+5 =1

subtracting 5 from both sides

-2y + 5 -5 = 1 -5

-2y = -4

dividing both sides by -2 gives

-2y / -2  = -4 / -2

y = 2

We got the value of y putting it in equation (iii) to get the value of x

as from equation (iii)

x = 10y-5

x = 10(2) - 5

x = 20 -5

x = 15

So this is the solution from the equations

b. b < 1 might be the correct answer

the answer is 0052

0 0 5 2

5 0 2 6 3 5

− 0

2 6

− 0

2 6 3

− 2 5 0

1 3 5

− 1 0 0

3 5