The cargo box of an 18-wheeler truck has an inside length of 39.6 feet, width of 7.6 feet, and a height of 8.8 feet. what is the carrying capacity (volume) of the cargo box of his truck? explain your thinking.

2,648.448 cubic feet

Step-by-step explanation:

The cargo box of a truck is a rectangular prism. The volume of a rectangular prism is l*w*h.

If the length is 39.6 ft, the width is 7.6 ft and the height is 8.8 ft then the volume is (39.6)(7.6)(8.8) = 2,648.448 cubic feet

yo answer should be 6 if im not mistaken

step-by-step explanation:

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47